5(x+-3)=2(x+1)+-5(x+-3)

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Solution for 5(x+-3)=2(x+1)+-5(x+-3) equation: 



5(x+-3)=2(x+1)+-5(x+-3)

We move all terms to the left:

5(x+-3)-(2(x+1)+-5(x+-3))=0

We add all the numbers together, and all the variables

5(x-3)-(2(x+1)+-5(x-3))=0

We use the square of the difference formula

5(x-3)-(2(x+1)-5(x-3))=0

We multiply parentheses

5x-(2(x+1)-5(x-3))-15=0



We calculate terms in parentheses: -(2(x+1)-5(x-3)), so:

2(x+1)-5(x-3)

We multiply parentheses

2x-5x+2+15

We add all the numbers together, and all the variables

-3x+17

Back to the equation:

-(-3x+17)



We get rid of parentheses

5x+3x-17-15=0

We add all the numbers together, and all the variables

8x-32=0

We move all terms containing x to the left, all other terms to the right

8x=32

x=32/8

x=4

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