5(x+-3)=4+-3(x+1)

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Solution for 5(x+-3)=4+-3(x+1) equation: 



5(x+-3)=4+-3(x+1)

We move all terms to the left:

5(x+-3)-(4+-3(x+1))=0

We add all the numbers together, and all the variables

5(x-3)-(4+-3(x+1))=0

We use the square of the difference formula

5(x-3)-(4-3(x+1))=0

We multiply parentheses

5x-(4-3(x+1))-15=0



We calculate terms in parentheses: -(4-3(x+1)), so:

4-3(x+1)

determiningTheFunctionDomain
-3(x+1)+4

We multiply parentheses

-3x-3+4

We add all the numbers together, and all the variables

-3x+1

Back to the equation:

-(-3x+1)



We get rid of parentheses

5x+3x-1-15=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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