5(x+-6)+2=7(x+2)+-10

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Solution for 5(x+-6)+2=7(x+2)+-10 equation: 



5(x+-6)+2=7(x+2)+-10

We move all terms to the left:

5(x+-6)+2-(7(x+2)+-10)=0

We add all the numbers together, and all the variables

5(x-6)-(7(x+2)+-10)+2=0

We use the square of the difference formula

5(x-6)-(7(x+2)-10)+2=0

We multiply parentheses

5x-(7(x+2)-10)-30+2=0



We calculate terms in parentheses: -(7(x+2)-10), so:

7(x+2)-10

We multiply parentheses

7x+14-10

We add all the numbers together, and all the variables

7x+4

Back to the equation:

-(7x+4)



We add all the numbers together, and all the variables

5x-(7x+4)-28=0

We get rid of parentheses

5x-7x-4-28=0

We add all the numbers together, and all the variables

-2x-32=0

We move all terms containing x to the left, all other terms to the right

-2x=32

x=32/-2

x=-16

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