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5(x+-7)=4x-33
We move all terms to the left:
5(x+-7)-(4x-33)=0
We add all the numbers together, and all the variables
5(x-7)-(4x-33)=0
We multiply parentheses
5x-(4x-33)-35=0
We get rid of parentheses
5x-4x+33-35=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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