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5(x+1)+10(2x-3)=2(3x-9)+5x-11
We move all terms to the left:
5(x+1)+10(2x-3)-(2(3x-9)+5x-11)=0
We multiply parentheses
5x+20x-(2(3x-9)+5x-11)+5-30=0
We calculate terms in parentheses: -(2(3x-9)+5x-11), so:We add all the numbers together, and all the variables
2(3x-9)+5x-11
We add all the numbers together, and all the variables
5x+2(3x-9)-11
We multiply parentheses
5x+6x-18-11
We add all the numbers together, and all the variables
11x-29
Back to the equation:
-(11x-29)
25x-(11x-29)-25=0
We get rid of parentheses
25x-11x+29-25=0
We add all the numbers together, and all the variables
14x+4=0
We move all terms containing x to the left, all other terms to the right
14x=-4
x=-4/14
x=-2/7
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