5(x+1)+10x-9=8+3(x-4)+12x

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Solution for 5(x+1)+10x-9=8+3(x-4)+12x equation: 



5(x+1)+10x-9=8+3(x-4)+12x

We move all terms to the left:

5(x+1)+10x-9-(8+3(x-4)+12x)=0

We add all the numbers together, and all the variables

10x+5(x+1)-(8+3(x-4)+12x)-9=0

We multiply parentheses

10x+5x-(8+3(x-4)+12x)+5-9=0



We calculate terms in parentheses: -(8+3(x-4)+12x), so:

8+3(x-4)+12x

determiningTheFunctionDomain
3(x-4)+12x+8

We add all the numbers together, and all the variables

12x+3(x-4)+8

We multiply parentheses

12x+3x-12+8

We add all the numbers together, and all the variables

15x-4

Back to the equation:

-(15x-4)



We add all the numbers together, and all the variables

15x-(15x-4)-4=0

We get rid of parentheses

15x-15x+4-4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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