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5(x+1)+1=2(2x+1)+x
We move all terms to the left:
5(x+1)+1-(2(2x+1)+x)=0
We multiply parentheses
5x-(2(2x+1)+x)+5+1=0
We calculate terms in parentheses: -(2(2x+1)+x), so:We add all the numbers together, and all the variables
2(2x+1)+x
We add all the numbers together, and all the variables
x+2(2x+1)
We multiply parentheses
x+4x+2
We add all the numbers together, and all the variables
5x+2
Back to the equation:
-(5x+2)
5x-(5x+2)+6=0
We get rid of parentheses
5x-5x-2+6=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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