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5(x+1)+1=3x+2(-3+x)
We move all terms to the left:
5(x+1)+1-(3x+2(-3+x))=0
We add all the numbers together, and all the variables
5(x+1)-(3x+2(x-3))+1=0
We multiply parentheses
5x-(3x+2(x-3))+5+1=0
We calculate terms in parentheses: -(3x+2(x-3)), so:We add all the numbers together, and all the variables
3x+2(x-3)
We multiply parentheses
3x+2x-6
We add all the numbers together, and all the variables
5x-6
Back to the equation:
-(5x-6)
5x-(5x-6)+6=0
We get rid of parentheses
5x-5x+6+6=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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