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5(x+1)+3x-6=(4x-3)
We move all terms to the left:
5(x+1)+3x-6-((4x-3))=0
We add all the numbers together, and all the variables
3x+5(x+1)-((4x-3))-6=0
We multiply parentheses
3x+5x-((4x-3))+5-6=0
We calculate terms in parentheses: -((4x-3)), so:We add all the numbers together, and all the variables
(4x-3)
We get rid of parentheses
4x-3
Back to the equation:
-(4x-3)
8x-(4x-3)-1=0
We get rid of parentheses
8x-4x+3-1=0
We add all the numbers together, and all the variables
4x+2=0
We move all terms containing x to the left, all other terms to the right
4x=-2
x=-2/4
x=-1/2
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