5(x+1)+3x=6-(4x+3)

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Solution for 5(x+1)+3x=6-(4x+3) equation: 



5(x+1)+3x=6-(4x+3)

We move all terms to the left:

5(x+1)+3x-(6-(4x+3))=0

We add all the numbers together, and all the variables

3x+5(x+1)-(6-(4x+3))=0

We multiply parentheses

3x+5x-(6-(4x+3))+5=0



We calculate terms in parentheses: -(6-(4x+3)), so:

6-(4x+3)

determiningTheFunctionDomain
-(4x+3)+6

We get rid of parentheses

-4x-3+6

We add all the numbers together, and all the variables

-4x+3

Back to the equation:

-(-4x+3)



We add all the numbers together, and all the variables

8x-(-4x+3)+5=0

We get rid of parentheses

8x+4x-3+5=0

We add all the numbers together, and all the variables

12x+2=0

We move all terms containing x to the left, all other terms to the right

12x=-2

x=-2/12

x=-1/6

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