5(x+1)+6(x+2)=(7x+3)

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Solution for 5(x+1)+6(x+2)=(7x+3) equation: 



5(x+1)+6(x+2)=(7x+3)

We move all terms to the left:

5(x+1)+6(x+2)-((7x+3))=0

We multiply parentheses

5x+6x-((7x+3))+5+12=0



We calculate terms in parentheses: -((7x+3)), so:

(7x+3)

We get rid of parentheses

7x+3

Back to the equation:

-(7x+3)



We add all the numbers together, and all the variables

11x-(7x+3)+17=0

We get rid of parentheses

11x-7x-3+17=0

We add all the numbers together, and all the variables

4x+14=0

We move all terms containing x to the left, all other terms to the right

4x=-14

x=-14/4

x=-3+1/2

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