5(x+1)+6(x-2)=7(x+3)

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Solution for 5(x+1)+6(x-2)=7(x+3) equation: 



5(x+1)+6(x-2)=7(x+3)

We move all terms to the left:

5(x+1)+6(x-2)-(7(x+3))=0

We multiply parentheses

5x+6x-(7(x+3))+5-12=0



We calculate terms in parentheses: -(7(x+3)), so:

7(x+3)

We multiply parentheses

7x+21

Back to the equation:

-(7x+21)



We add all the numbers together, and all the variables

11x-(7x+21)-7=0

We get rid of parentheses

11x-7x-21-7=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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