5(x+1)+6(x-3)=20+7x-11

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Solution for 5(x+1)+6(x-3)=20+7x-11 equation: 



5(x+1)+6(x-3)=20+7x-11

We move all terms to the left:

5(x+1)+6(x-3)-(20+7x-11)=0

We add all the numbers together, and all the variables

5(x+1)+6(x-3)-(7x+9)=0

We multiply parentheses

5x+6x-(7x+9)+5-18=0

We get rid of parentheses

5x+6x-7x-9+5-18=0

We add all the numbers together, and all the variables

4x-22=0

We move all terms containing x to the left, all other terms to the right

4x=22

x=22/4

x=5+1/2

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