5(x+1)+6=3(4+x)+(2x-1)

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Solution for 5(x+1)+6=3(4+x)+(2x-1) equation:


Simplifying
5(x + 1) + 6 = 3(4 + x) + (2x + -1)

Reorder the terms:
5(1 + x) + 6 = 3(4 + x) + (2x + -1)
(1 * 5 + x * 5) + 6 = 3(4 + x) + (2x + -1)
(5 + 5x) + 6 = 3(4 + x) + (2x + -1)

Reorder the terms:
5 + 6 + 5x = 3(4 + x) + (2x + -1)

Combine like terms: 5 + 6 = 11
11 + 5x = 3(4 + x) + (2x + -1)
11 + 5x = (4 * 3 + x * 3) + (2x + -1)
11 + 5x = (12 + 3x) + (2x + -1)

Reorder the terms:
11 + 5x = 12 + 3x + (-1 + 2x)

Remove parenthesis around (-1 + 2x)
11 + 5x = 12 + 3x + -1 + 2x

Reorder the terms:
11 + 5x = 12 + -1 + 3x + 2x

Combine like terms: 12 + -1 = 11
11 + 5x = 11 + 3x + 2x

Combine like terms: 3x + 2x = 5x
11 + 5x = 11 + 5x

Add '-11' to each side of the equation.
11 + -11 + 5x = 11 + -11 + 5x

Combine like terms: 11 + -11 = 0
0 + 5x = 11 + -11 + 5x
5x = 11 + -11 + 5x

Combine like terms: 11 + -11 = 0
5x = 0 + 5x
5x = 5x

Add '-5x' to each side of the equation.
5x + -5x = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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