5(x+1)+8=2x-4(3x+2)

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Solution for 5(x+1)+8=2x-4(3x+2) equation:


Simplifying
5(x + 1) + 8 = 2x + -4(3x + 2)

Reorder the terms:
5(1 + x) + 8 = 2x + -4(3x + 2)
(1 * 5 + x * 5) + 8 = 2x + -4(3x + 2)
(5 + 5x) + 8 = 2x + -4(3x + 2)

Reorder the terms:
5 + 8 + 5x = 2x + -4(3x + 2)

Combine like terms: 5 + 8 = 13
13 + 5x = 2x + -4(3x + 2)

Reorder the terms:
13 + 5x = 2x + -4(2 + 3x)
13 + 5x = 2x + (2 * -4 + 3x * -4)
13 + 5x = 2x + (-8 + -12x)

Reorder the terms:
13 + 5x = -8 + 2x + -12x

Combine like terms: 2x + -12x = -10x
13 + 5x = -8 + -10x

Solving
13 + 5x = -8 + -10x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '10x' to each side of the equation.
13 + 5x + 10x = -8 + -10x + 10x

Combine like terms: 5x + 10x = 15x
13 + 15x = -8 + -10x + 10x

Combine like terms: -10x + 10x = 0
13 + 15x = -8 + 0
13 + 15x = -8

Add '-13' to each side of the equation.
13 + -13 + 15x = -8 + -13

Combine like terms: 13 + -13 = 0
0 + 15x = -8 + -13
15x = -8 + -13

Combine like terms: -8 + -13 = -21
15x = -21

Divide each side by '15'.
x = -1.4

Simplifying
x = -1.4

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