5(x+1)+x=3(x-2)+2

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Solution for 5(x+1)+x=3(x-2)+2 equation: 



5(x+1)+x=3(x-2)+2

We move all terms to the left:

5(x+1)+x-(3(x-2)+2)=0

We add all the numbers together, and all the variables

x+5(x+1)-(3(x-2)+2)=0

We multiply parentheses

x+5x-(3(x-2)+2)+5=0



We calculate terms in parentheses: -(3(x-2)+2), so:

3(x-2)+2

We multiply parentheses

3x-6+2

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We add all the numbers together, and all the variables

6x-(3x-4)+5=0

We get rid of parentheses

6x-3x+4+5=0

We add all the numbers together, and all the variables

3x+9=0

We move all terms containing x to the left, all other terms to the right

3x=-9

x=-9/3

x=-3

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