5(x+1)-1(x-7)=4(x+2)

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Solution for 5(x+1)-1(x-7)=4(x+2) equation:


Simplifying
5(x + 1) + -1(x + -7) = 4(x + 2)

Reorder the terms:
5(1 + x) + -1(x + -7) = 4(x + 2)
(1 * 5 + x * 5) + -1(x + -7) = 4(x + 2)
(5 + 5x) + -1(x + -7) = 4(x + 2)

Reorder the terms:
5 + 5x + -1(-7 + x) = 4(x + 2)
5 + 5x + (-7 * -1 + x * -1) = 4(x + 2)
5 + 5x + (7 + -1x) = 4(x + 2)

Reorder the terms:
5 + 7 + 5x + -1x = 4(x + 2)

Combine like terms: 5 + 7 = 12
12 + 5x + -1x = 4(x + 2)

Combine like terms: 5x + -1x = 4x
12 + 4x = 4(x + 2)

Reorder the terms:
12 + 4x = 4(2 + x)
12 + 4x = (2 * 4 + x * 4)
12 + 4x = (8 + 4x)

Add '-4x' to each side of the equation.
12 + 4x + -4x = 8 + 4x + -4x

Combine like terms: 4x + -4x = 0
12 + 0 = 8 + 4x + -4x
12 = 8 + 4x + -4x

Combine like terms: 4x + -4x = 0
12 = 8 + 0
12 = 8

Solving
12 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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