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5(x+1)-2=2(3+x)
We move all terms to the left:
5(x+1)-2-(2(3+x))=0
We add all the numbers together, and all the variables
5(x+1)-(2(x+3))-2=0
We multiply parentheses
5x-(2(x+3))+5-2=0
We calculate terms in parentheses: -(2(x+3)), so:We add all the numbers together, and all the variables
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
5x-(2x+6)+3=0
We get rid of parentheses
5x-2x-6+3=0
We add all the numbers together, and all the variables
3x-3=0
We move all terms containing x to the left, all other terms to the right
3x=3
x=3/3
x=1
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