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5(x+1)-3=x-(2+x)
We move all terms to the left:
5(x+1)-3-(x-(2+x))=0
We add all the numbers together, and all the variables
5(x+1)-(x-(x+2))-3=0
We multiply parentheses
5x-(x-(x+2))+5-3=0
We calculate terms in parentheses: -(x-(x+2)), so:We add all the numbers together, and all the variables
x-(x+2)
We get rid of parentheses
x-x-2
We add all the numbers together, and all the variables
-2
Back to the equation:
-(-2)
5x+4=0
We move all terms containing x to the left, all other terms to the right
5x=-4
x=-4/5
x=-4/5
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