5(x+1)-4(x-2)=2(7+x)

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Solution for 5(x+1)-4(x-2)=2(7+x) equation: 



5(x+1)-4(x-2)=2(7+x)

We move all terms to the left:

5(x+1)-4(x-2)-(2(7+x))=0

We add all the numbers together, and all the variables

5(x+1)-4(x-2)-(2(x+7))=0

We multiply parentheses

5x-4x-(2(x+7))+5+8=0



We calculate terms in parentheses: -(2(x+7)), so:

2(x+7)

We multiply parentheses

2x+14

Back to the equation:

-(2x+14)



We add all the numbers together, and all the variables

x-(2x+14)+13=0

We get rid of parentheses

x-2x-14+13=0

We add all the numbers together, and all the variables

-1x-1=0

We move all terms containing x to the left, all other terms to the right

-x=1

x=1/-1

x=-1

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