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5(x+1)-8=5x(2-4)
We move all terms to the left:
5(x+1)-8-(5x(2-4))=0
We add all the numbers together, and all the variables
5(x+1)-(5x(-2))-8=0
We multiply parentheses
5x-(5x(-2))+5-8=0
We calculate terms in parentheses: -(5x(-2)), so:We add all the numbers together, and all the variables
5x(-2)
We multiply parentheses
-10x
Back to the equation:
-(-10x)
5x-(-10x)-3=0
We get rid of parentheses
5x+10x-3=0
We add all the numbers together, and all the variables
15x-3=0
We move all terms containing x to the left, all other terms to the right
15x=3
x=3/15
x=1/5
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