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5(x+1)=-(10x-5)+9x
We move all terms to the left:
5(x+1)-(-(10x-5)+9x)=0
We multiply parentheses
5x-(-(10x-5)+9x)+5=0
We calculate terms in parentheses: -(-(10x-5)+9x), so:We get rid of parentheses
-(10x-5)+9x
We add all the numbers together, and all the variables
9x-(10x-5)
We get rid of parentheses
9x-10x+5
We add all the numbers together, and all the variables
-1x+5
Back to the equation:
-(-1x+5)
5x+1x-5+5=0
We add all the numbers together, and all the variables
6x=0
x=0/6
x=0
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