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5(x+1)=2(2-x)
We move all terms to the left:
5(x+1)-(2(2-x))=0
We add all the numbers together, and all the variables
5(x+1)-(2(-1x+2))=0
We multiply parentheses
5x-(2(-1x+2))+5=0
We calculate terms in parentheses: -(2(-1x+2)), so:We get rid of parentheses
2(-1x+2)
We multiply parentheses
-2x+4
Back to the equation:
-(-2x+4)
5x+2x-4+5=0
We add all the numbers together, and all the variables
7x+1=0
We move all terms containing x to the left, all other terms to the right
7x=-1
x=-1/7
x=-1/7
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