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5(x+1)=2x+4(x+1)
We move all terms to the left:
5(x+1)-(2x+4(x+1))=0
We multiply parentheses
5x-(2x+4(x+1))+5=0
We calculate terms in parentheses: -(2x+4(x+1)), so:We get rid of parentheses
2x+4(x+1)
We multiply parentheses
2x+4x+4
We add all the numbers together, and all the variables
6x+4
Back to the equation:
-(6x+4)
5x-6x-4+5=0
We add all the numbers together, and all the variables
-1x+1=0
We move all terms containing x to the left, all other terms to the right
-x=-1
x=-1/-1
x=1
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