5(x+1)=3(2x-5)-(1-3x)

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Solution for 5(x+1)=3(2x-5)-(1-3x) equation: 



5(x+1)=3(2x-5)-(1-3x)

We move all terms to the left:

5(x+1)-(3(2x-5)-(1-3x))=0

We add all the numbers together, and all the variables

5(x+1)-(3(2x-5)-(-3x+1))=0

We multiply parentheses

5x-(3(2x-5)-(-3x+1))+5=0



We calculate terms in parentheses: -(3(2x-5)-(-3x+1)), so:

3(2x-5)-(-3x+1)

We multiply parentheses

6x-(-3x+1)-15

We get rid of parentheses

6x+3x-1-15

We add all the numbers together, and all the variables

9x-16

Back to the equation:

-(9x-16)



We get rid of parentheses

5x-9x+16+5=0

We add all the numbers together, and all the variables

-4x+21=0

We move all terms containing x to the left, all other terms to the right

-4x=-21

x=-21/-4

x=5+1/4

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