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5(x+1)=3(2x-5)-(1-3x)
We move all terms to the left:
5(x+1)-(3(2x-5)-(1-3x))=0
We add all the numbers together, and all the variables
5(x+1)-(3(2x-5)-(-3x+1))=0
We multiply parentheses
5x-(3(2x-5)-(-3x+1))+5=0
We calculate terms in parentheses: -(3(2x-5)-(-3x+1)), so:We get rid of parentheses
3(2x-5)-(-3x+1)
We multiply parentheses
6x-(-3x+1)-15
We get rid of parentheses
6x+3x-1-15
We add all the numbers together, and all the variables
9x-16
Back to the equation:
-(9x-16)
5x-9x+16+5=0
We add all the numbers together, and all the variables
-4x+21=0
We move all terms containing x to the left, all other terms to the right
-4x=-21
x=-21/-4
x=5+1/4
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