5(x+1)=3(x+1)+2(x+1)

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Solution for 5(x+1)=3(x+1)+2(x+1) equation:


Simplifying
5(x + 1) = 3(x + 1) + 2(x + 1)

Reorder the terms:
5(1 + x) = 3(x + 1) + 2(x + 1)
(1 * 5 + x * 5) = 3(x + 1) + 2(x + 1)
(5 + 5x) = 3(x + 1) + 2(x + 1)

Reorder the terms:
5 + 5x = 3(1 + x) + 2(x + 1)
5 + 5x = (1 * 3 + x * 3) + 2(x + 1)
5 + 5x = (3 + 3x) + 2(x + 1)

Reorder the terms:
5 + 5x = 3 + 3x + 2(1 + x)
5 + 5x = 3 + 3x + (1 * 2 + x * 2)
5 + 5x = 3 + 3x + (2 + 2x)

Reorder the terms:
5 + 5x = 3 + 2 + 3x + 2x

Combine like terms: 3 + 2 = 5
5 + 5x = 5 + 3x + 2x

Combine like terms: 3x + 2x = 5x
5 + 5x = 5 + 5x

Add '-5' to each side of the equation.
5 + -5 + 5x = 5 + -5 + 5x

Combine like terms: 5 + -5 = 0
0 + 5x = 5 + -5 + 5x
5x = 5 + -5 + 5x

Combine like terms: 5 + -5 = 0
5x = 0 + 5x
5x = 5x

Add '-5x' to each side of the equation.
5x + -5x = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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