5(x+1)=4-(x-2)

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Solution for 5(x+1)=4-(x-2) equation: 



5(x+1)=4-(x-2)

We move all terms to the left:

5(x+1)-(4-(x-2))=0

We multiply parentheses

5x-(4-(x-2))+5=0



We calculate terms in parentheses: -(4-(x-2)), so:

4-(x-2)

determiningTheFunctionDomain
-(x-2)+4

We get rid of parentheses

-x+2+4

We add all the numbers together, and all the variables

-1x+6

Back to the equation:

-(-1x+6)



We get rid of parentheses

5x+1x-6+5=0

We add all the numbers together, and all the variables

6x-1=0

We move all terms containing x to the left, all other terms to the right

6x=1

x=1/6

x=1/6

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