5(x+10)+2(x-5)=6(x+3)

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Solution for 5(x+10)+2(x-5)=6(x+3) equation: 



5(x+10)+2(x-5)=6(x+3)

We move all terms to the left:

5(x+10)+2(x-5)-(6(x+3))=0

We multiply parentheses

5x+2x-(6(x+3))+50-10=0



We calculate terms in parentheses: -(6(x+3)), so:

6(x+3)

We multiply parentheses

6x+18

Back to the equation:

-(6x+18)



We add all the numbers together, and all the variables

7x-(6x+18)+40=0

We get rid of parentheses

7x-6x-18+40=0

We add all the numbers together, and all the variables

x+22=0

We move all terms containing x to the left, all other terms to the right

x=-22

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