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5(x+12)=2(x-3)
We move all terms to the left:
5(x+12)-(2(x-3))=0
We multiply parentheses
5x-(2(x-3))+60=0
We calculate terms in parentheses: -(2(x-3)), so:We get rid of parentheses
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
5x-2x+6+60=0
We add all the numbers together, and all the variables
3x+66=0
We move all terms containing x to the left, all other terms to the right
3x=-66
x=-66/3
x=-22
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