5(x+16)+36x=2(x+18)-200

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Solution for 5(x+16)+36x=2(x+18)-200 equation: 



5(x+16)+36x=2(x+18)-200

We move all terms to the left:

5(x+16)+36x-(2(x+18)-200)=0

We add all the numbers together, and all the variables

36x+5(x+16)-(2(x+18)-200)=0

We multiply parentheses

36x+5x-(2(x+18)-200)+80=0



We calculate terms in parentheses: -(2(x+18)-200), so:

2(x+18)-200

We multiply parentheses

2x+36-200

We add all the numbers together, and all the variables

2x-164

Back to the equation:

-(2x-164)



We add all the numbers together, and all the variables

41x-(2x-164)+80=0

We get rid of parentheses

41x-2x+164+80=0

We add all the numbers together, and all the variables

39x+244=0

We move all terms containing x to the left, all other terms to the right

39x=-244

x=-244/39

x=-6+10/39

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