5(x+2)(x+2)-29(x+2)=6

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Solution for 5(x+2)(x+2)-29(x+2)=6 equation:


Simplifying
5(x + 2)(x + 2) + -29(x + 2) = 6

Reorder the terms:
5(2 + x)(x + 2) + -29(x + 2) = 6

Reorder the terms:
5(2 + x)(2 + x) + -29(x + 2) = 6

Multiply (2 + x) * (2 + x)
5(2(2 + x) + x(2 + x)) + -29(x + 2) = 6
5((2 * 2 + x * 2) + x(2 + x)) + -29(x + 2) = 6
5((4 + 2x) + x(2 + x)) + -29(x + 2) = 6
5(4 + 2x + (2 * x + x * x)) + -29(x + 2) = 6
5(4 + 2x + (2x + x2)) + -29(x + 2) = 6

Combine like terms: 2x + 2x = 4x
5(4 + 4x + x2) + -29(x + 2) = 6
(4 * 5 + 4x * 5 + x2 * 5) + -29(x + 2) = 6
(20 + 20x + 5x2) + -29(x + 2) = 6

Reorder the terms:
20 + 20x + 5x2 + -29(2 + x) = 6
20 + 20x + 5x2 + (2 * -29 + x * -29) = 6
20 + 20x + 5x2 + (-58 + -29x) = 6

Reorder the terms:
20 + -58 + 20x + -29x + 5x2 = 6

Combine like terms: 20 + -58 = -38
-38 + 20x + -29x + 5x2 = 6

Combine like terms: 20x + -29x = -9x
-38 + -9x + 5x2 = 6

Solving
-38 + -9x + 5x2 = 6

Solving for variable 'x'.

Reorder the terms:
-38 + -6 + -9x + 5x2 = 6 + -6

Combine like terms: -38 + -6 = -44
-44 + -9x + 5x2 = 6 + -6

Combine like terms: 6 + -6 = 0
-44 + -9x + 5x2 = 0

Factor a trinomial.
(-11 + -5x)(4 + -1x) = 0

Subproblem 1

Set the factor '(-11 + -5x)' equal to zero and attempt to solve: Simplifying -11 + -5x = 0 Solving -11 + -5x = 0 Move all terms containing x to the left, all other terms to the right. Add '11' to each side of the equation. -11 + 11 + -5x = 0 + 11 Combine like terms: -11 + 11 = 0 0 + -5x = 0 + 11 -5x = 0 + 11 Combine like terms: 0 + 11 = 11 -5x = 11 Divide each side by '-5'. x = -2.2 Simplifying x = -2.2

Subproblem 2

Set the factor '(4 + -1x)' equal to zero and attempt to solve: Simplifying 4 + -1x = 0 Solving 4 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1x = 0 + -4 -1x = 0 + -4 Combine like terms: 0 + -4 = -4 -1x = -4 Divide each side by '-1'. x = 4 Simplifying x = 4

Solution

x = {-2.2, 4}

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