5(x+2)+19=4(x+3)

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Solution for 5(x+2)+19=4(x+3) equation: 



5(x+2)+19=4(x+3)

We move all terms to the left:

5(x+2)+19-(4(x+3))=0

We multiply parentheses

5x-(4(x+3))+10+19=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

5x-(4x+12)+29=0

We get rid of parentheses

5x-4x-12+29=0

We add all the numbers together, and all the variables

x+17=0

We move all terms containing x to the left, all other terms to the right

x=-17

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