5(x+2)+2(x-1)=7(x-4)

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Solution for 5(x+2)+2(x-1)=7(x-4) equation:


Simplifying
5(x + 2) + 2(x + -1) = 7(x + -4)

Reorder the terms:
5(2 + x) + 2(x + -1) = 7(x + -4)
(2 * 5 + x * 5) + 2(x + -1) = 7(x + -4)
(10 + 5x) + 2(x + -1) = 7(x + -4)

Reorder the terms:
10 + 5x + 2(-1 + x) = 7(x + -4)
10 + 5x + (-1 * 2 + x * 2) = 7(x + -4)
10 + 5x + (-2 + 2x) = 7(x + -4)

Reorder the terms:
10 + -2 + 5x + 2x = 7(x + -4)

Combine like terms: 10 + -2 = 8
8 + 5x + 2x = 7(x + -4)

Combine like terms: 5x + 2x = 7x
8 + 7x = 7(x + -4)

Reorder the terms:
8 + 7x = 7(-4 + x)
8 + 7x = (-4 * 7 + x * 7)
8 + 7x = (-28 + 7x)

Add '-7x' to each side of the equation.
8 + 7x + -7x = -28 + 7x + -7x

Combine like terms: 7x + -7x = 0
8 + 0 = -28 + 7x + -7x
8 = -28 + 7x + -7x

Combine like terms: 7x + -7x = 0
8 = -28 + 0
8 = -28

Solving
8 = -28

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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