5(x+2)+3(4-x)=3(x-1)+7

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Solution for 5(x+2)+3(4-x)=3(x-1)+7 equation:



5(x+2)+3(4-x)=3(x-1)+7
We move all terms to the left:
5(x+2)+3(4-x)-(3(x-1)+7)=0
We add all the numbers together, and all the variables
5(x+2)+3(-1x+4)-(3(x-1)+7)=0
We multiply parentheses
5x-3x-(3(x-1)+7)+10+12=0
We calculate terms in parentheses: -(3(x-1)+7), so:
3(x-1)+7
We multiply parentheses
3x-3+7
We add all the numbers together, and all the variables
3x+4
Back to the equation:
-(3x+4)
We add all the numbers together, and all the variables
2x-(3x+4)+22=0
We get rid of parentheses
2x-3x-4+22=0
We add all the numbers together, and all the variables
-1x+18=0
We move all terms containing x to the left, all other terms to the right
-x=-18
x=-18/-1
x=+18

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