5(x+2)+3=9+3(2x-1)

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Solution for 5(x+2)+3=9+3(2x-1) equation: 



5(x+2)+3=9+3(2x-1)

We move all terms to the left:

5(x+2)+3-(9+3(2x-1))=0

We multiply parentheses

5x-(9+3(2x-1))+10+3=0



We calculate terms in parentheses: -(9+3(2x-1)), so:

9+3(2x-1)

determiningTheFunctionDomain
3(2x-1)+9

We multiply parentheses

6x-3+9

We add all the numbers together, and all the variables

6x+6

Back to the equation:

-(6x+6)



We add all the numbers together, and all the variables

5x-(6x+6)+13=0

We get rid of parentheses

5x-6x-6+13=0

We add all the numbers together, and all the variables

-1x+7=0

We move all terms containing x to the left, all other terms to the right

-x=-7

x=-7/-1

x=+7

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