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5(x+2)+5=3(x+5)+2x
We move all terms to the left:
5(x+2)+5-(3(x+5)+2x)=0
We multiply parentheses
5x-(3(x+5)+2x)+10+5=0
We calculate terms in parentheses: -(3(x+5)+2x), so:We add all the numbers together, and all the variables
3(x+5)+2x
We add all the numbers together, and all the variables
2x+3(x+5)
We multiply parentheses
2x+3x+15
We add all the numbers together, and all the variables
5x+15
Back to the equation:
-(5x+15)
5x-(5x+15)+15=0
We get rid of parentheses
5x-5x-15+15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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