5(x+2)+6(x-3)=7-(x+4)

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Solution for 5(x+2)+6(x-3)=7-(x+4) equation: 



5(x+2)+6(x-3)=7-(x+4)

We move all terms to the left:

5(x+2)+6(x-3)-(7-(x+4))=0

We multiply parentheses

5x+6x-(7-(x+4))+10-18=0



We calculate terms in parentheses: -(7-(x+4)), so:

7-(x+4)

determiningTheFunctionDomain
-(x+4)+7

We get rid of parentheses

-x-4+7

We add all the numbers together, and all the variables

-1x+3

Back to the equation:

-(-1x+3)



We add all the numbers together, and all the variables

11x-(-1x+3)-8=0

We get rid of parentheses

11x+1x-3-8=0

We add all the numbers together, and all the variables

12x-11=0

We move all terms containing x to the left, all other terms to the right

12x=11

x=11/12

x=11/12

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