5(x+2)-(x-5)=(2x-3)(2x+3)+19

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Solution for 5(x+2)-(x-5)=(2x-3)(2x+3)+19 equation:



5(x+2)-(x-5)=(2x-3)(2x+3)+19
We move all terms to the left:
5(x+2)-(x-5)-((2x-3)(2x+3)+19)=0
We use the square of the difference formula
4x^2+5(x+2)-(x-5)+9=0
We multiply parentheses
4x^2+5x-(x-5)+10+9=0
We get rid of parentheses
4x^2+5x-x+5+10+9=0
We add all the numbers together, and all the variables
4x^2+4x+24=0
a = 4; b = 4; c = +24;
Δ = b2-4ac
Δ = 42-4·4·24
Δ = -368
Delta is less than zero, so there is no solution for the equation

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