5(x+2)-(x-5)=(2x-3)(2x+3)+19

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Solution for 5(x+2)-(x-5)=(2x-3)(2x+3)+19 equation: 



5(x+2)-(x-5)=(2x-3)(2x+3)+19

We move all terms to the left:

5(x+2)-(x-5)-((2x-3)(2x+3)+19)=0

We use the square of the difference formula

4x^2+5(x+2)-(x-5)+9=0

We multiply parentheses

4x^2+5x-(x-5)+10+9=0

We get rid of parentheses

4x^2+5x-x+5+10+9=0

We add all the numbers together, and all the variables

4x^2+4x+24=0

a = 4; b = 4; c = +24;
Δ = b2-4ac
Δ = 42-4·4·24
Δ = -368
Delta is less than zero, so there is no solution for the equation

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