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5(x+2)-2(3-2x)=3(x-5)-4(4-x)
We move all terms to the left:
5(x+2)-2(3-2x)-(3(x-5)-4(4-x))=0
We add all the numbers together, and all the variables
5(x+2)-2(-2x+3)-(3(x-5)-4(-1x+4))=0
We multiply parentheses
5x+4x-(3(x-5)-4(-1x+4))+10-6=0
We calculate terms in parentheses: -(3(x-5)-4(-1x+4)), so:We add all the numbers together, and all the variables
3(x-5)-4(-1x+4)
We multiply parentheses
3x+4x-15-16
We add all the numbers together, and all the variables
7x-31
Back to the equation:
-(7x-31)
9x-(7x-31)+4=0
We get rid of parentheses
9x-7x+31+4=0
We add all the numbers together, and all the variables
2x+35=0
We move all terms containing x to the left, all other terms to the right
2x=-35
x=-35/2
x=-17+1/2
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