5(x+2)-2(3-2x)=3(x-5)-4(4-x)

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Solution for 5(x+2)-2(3-2x)=3(x-5)-4(4-x) equation: 



5(x+2)-2(3-2x)=3(x-5)-4(4-x)

We move all terms to the left:

5(x+2)-2(3-2x)-(3(x-5)-4(4-x))=0

We add all the numbers together, and all the variables

5(x+2)-2(-2x+3)-(3(x-5)-4(-1x+4))=0

We multiply parentheses

5x+4x-(3(x-5)-4(-1x+4))+10-6=0



We calculate terms in parentheses: -(3(x-5)-4(-1x+4)), so:

3(x-5)-4(-1x+4)

We multiply parentheses

3x+4x-15-16

We add all the numbers together, and all the variables

7x-31

Back to the equation:

-(7x-31)



We add all the numbers together, and all the variables

9x-(7x-31)+4=0

We get rid of parentheses

9x-7x+31+4=0

We add all the numbers together, and all the variables

2x+35=0

We move all terms containing x to the left, all other terms to the right

2x=-35

x=-35/2

x=-17+1/2

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