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5(x+2)-3=2x+3(2+x)
We move all terms to the left:
5(x+2)-3-(2x+3(2+x))=0
We add all the numbers together, and all the variables
5(x+2)-(2x+3(x+2))-3=0
We multiply parentheses
5x-(2x+3(x+2))+10-3=0
We calculate terms in parentheses: -(2x+3(x+2)), so:We add all the numbers together, and all the variables
2x+3(x+2)
We multiply parentheses
2x+3x+6
We add all the numbers together, and all the variables
5x+6
Back to the equation:
-(5x+6)
5x-(5x+6)+7=0
We get rid of parentheses
5x-5x-6+7=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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