5(x+2)-3x=8-2(3x+1)

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Solution for 5(x+2)-3x=8-2(3x+1) equation: 



5(x+2)-3x=8-2(3x+1)

We move all terms to the left:

5(x+2)-3x-(8-2(3x+1))=0

We add all the numbers together, and all the variables

-3x+5(x+2)-(8-2(3x+1))=0

We multiply parentheses

-3x+5x-(8-2(3x+1))+10=0



We calculate terms in parentheses: -(8-2(3x+1)), so:

8-2(3x+1)

determiningTheFunctionDomain
-2(3x+1)+8

We multiply parentheses

-6x-2+8

We add all the numbers together, and all the variables

-6x+6

Back to the equation:

-(-6x+6)



We add all the numbers together, and all the variables

2x-(-6x+6)+10=0

We get rid of parentheses

2x+6x-6+10=0

We add all the numbers together, and all the variables

8x+4=0

We move all terms containing x to the left, all other terms to the right

8x=-4

x=-4/8

x=-1/2

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