5(x+2)-4(1+3x)=20

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Solution for 5(x+2)-4(1+3x)=20 equation:



5(x+2)-4(1+3x)=20
We move all terms to the left:
5(x+2)-4(1+3x)-(20)=0
We add all the numbers together, and all the variables
5(x+2)-4(3x+1)-20=0
We multiply parentheses
5x-12x+10-4-20=0
We add all the numbers together, and all the variables
-7x-14=0
We move all terms containing x to the left, all other terms to the right
-7x=14
x=14/-7
x=-2

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