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5(x+2)-4=2x+3(1+x)
We move all terms to the left:
5(x+2)-4-(2x+3(1+x))=0
We add all the numbers together, and all the variables
5(x+2)-(2x+3(x+1))-4=0
We multiply parentheses
5x-(2x+3(x+1))+10-4=0
We calculate terms in parentheses: -(2x+3(x+1)), so:We add all the numbers together, and all the variables
2x+3(x+1)
We multiply parentheses
2x+3x+3
We add all the numbers together, and all the variables
5x+3
Back to the equation:
-(5x+3)
5x-(5x+3)+6=0
We get rid of parentheses
5x-5x-3+6=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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