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5(x+2)-4=5(x-2)
We move all terms to the left:
5(x+2)-4-(5(x-2))=0
We multiply parentheses
5x-(5(x-2))+10-4=0
We calculate terms in parentheses: -(5(x-2)), so:We add all the numbers together, and all the variables
5(x-2)
We multiply parentheses
5x-10
Back to the equation:
-(5x-10)
5x-(5x-10)+6=0
We get rid of parentheses
5x-5x+10+6=0
We add all the numbers together, and all the variables
16!=0
There is no solution for this equation
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