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5(x+2)-7=3(x+1)
We move all terms to the left:
5(x+2)-7-(3(x+1))=0
We multiply parentheses
5x-(3(x+1))+10-7=0
We calculate terms in parentheses: -(3(x+1)), so:We add all the numbers together, and all the variables
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
5x-(3x+3)+3=0
We get rid of parentheses
5x-3x-3+3=0
We add all the numbers together, and all the variables
2x=0
x=0/2
x=0
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