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5(x+2)-9x=7-3(x+1)
We move all terms to the left:
5(x+2)-9x-(7-3(x+1))=0
We add all the numbers together, and all the variables
-9x+5(x+2)-(7-3(x+1))=0
We multiply parentheses
-9x+5x-(7-3(x+1))+10=0
We calculate terms in parentheses: -(7-3(x+1)), so:We add all the numbers together, and all the variables
7-3(x+1)
determiningTheFunctionDomain -3(x+1)+7
We multiply parentheses
-3x-3+7
We add all the numbers together, and all the variables
-3x+4
Back to the equation:
-(-3x+4)
-4x-(-3x+4)+10=0
We get rid of parentheses
-4x+3x-4+10=0
We add all the numbers together, and all the variables
-1x+6=0
We move all terms containing x to the left, all other terms to the right
-x=-6
x=-6/-1
x=+6
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