5(x+2)-9x=7-3(x+1)

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Solution for 5(x+2)-9x=7-3(x+1) equation: 



5(x+2)-9x=7-3(x+1)

We move all terms to the left:

5(x+2)-9x-(7-3(x+1))=0

We add all the numbers together, and all the variables

-9x+5(x+2)-(7-3(x+1))=0

We multiply parentheses

-9x+5x-(7-3(x+1))+10=0



We calculate terms in parentheses: -(7-3(x+1)), so:

7-3(x+1)

determiningTheFunctionDomain
-3(x+1)+7

We multiply parentheses

-3x-3+7

We add all the numbers together, and all the variables

-3x+4

Back to the equation:

-(-3x+4)



We add all the numbers together, and all the variables

-4x-(-3x+4)+10=0

We get rid of parentheses

-4x+3x-4+10=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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