5(x+2)3x=29

Solution for 5(x+2)3x=29 equation:

5(x+2)3x=29

We move all terms to the left:

5(x+2)3x-(29)=0

We multiply parentheses

15x^2+30x-29=0

a = 15; b = 30; c = -29;
Δ = b2-4ac
Δ = 302-4·15·(-29)
Δ = 2640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2640}=\sqrt{16*165}=\sqrt{16}*\sqrt{165}=4\sqrt{165}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-4\sqrt{165}}{2*15}=\frac{-30-4\sqrt{165}}{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+4\sqrt{165}}{2*15}=\frac{-30+4\sqrt{165}}{30}
$