5(x+2)=-5-2(x-3)

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Solution for 5(x+2)=-5-2(x-3) equation: 



5(x+2)=-5-2(x-3)

We move all terms to the left:

5(x+2)-(-5-2(x-3))=0

We multiply parentheses

5x-(-5-2(x-3))+10=0



We calculate terms in parentheses: -(-5-2(x-3)), so:

-5-2(x-3)

determiningTheFunctionDomain
-2(x-3)-5

We multiply parentheses

-2x+6-5

We add all the numbers together, and all the variables

-2x+1

Back to the equation:

-(-2x+1)



We get rid of parentheses

5x+2x-1+10=0

We add all the numbers together, and all the variables

7x+9=0

We move all terms containing x to the left, all other terms to the right

7x=-9

x=-9/7

x=-1+2/7

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