5(x+2)=1-2(x+3)

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Solution for 5(x+2)=1-2(x+3) equation: 



5(x+2)=1-2(x+3)

We move all terms to the left:

5(x+2)-(1-2(x+3))=0

We multiply parentheses

5x-(1-2(x+3))+10=0



We calculate terms in parentheses: -(1-2(x+3)), so:

1-2(x+3)

determiningTheFunctionDomain
-2(x+3)+1

We multiply parentheses

-2x-6+1

We add all the numbers together, and all the variables

-2x-5

Back to the equation:

-(-2x-5)



We get rid of parentheses

5x+2x+5+10=0

We add all the numbers together, and all the variables

7x+15=0

We move all terms containing x to the left, all other terms to the right

7x=-15

x=-15/7

x=-2+1/7

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