5(x+2)=16+3(2x-1)

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Solution for 5(x+2)=16+3(2x-1) equation: 



5(x+2)=16+3(2x-1)

We move all terms to the left:

5(x+2)-(16+3(2x-1))=0

We multiply parentheses

5x-(16+3(2x-1))+10=0



We calculate terms in parentheses: -(16+3(2x-1)), so:

16+3(2x-1)

determiningTheFunctionDomain
3(2x-1)+16

We multiply parentheses

6x-3+16

We add all the numbers together, and all the variables

6x+13

Back to the equation:

-(6x+13)



We get rid of parentheses

5x-6x-13+10=0

We add all the numbers together, and all the variables

-1x-3=0

We move all terms containing x to the left, all other terms to the right

-x=3

x=3/-1

x=-3

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